Question

each of two equal angles of a triangle is twice the third angle. find the angles of the triangle.​

Answer 1

Answer:

Let the 1st and second angle of triangle=X

the 3nd angle of triangle=2x

X +X+2x =180°

4x=180°

X =180°÷4

=45°

3rd angle 2x

= 2×45

=90°

1st angle =45°

2nd angle= 45°

3rd angle= 90°

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Step-by-step explanation:

Answer 2

Answer:

45° 45° and 90°

is the correct answer.....