Question

Each of two equal angles of a triangle is twice the third angle; find the angles of the triangle.​

Answer 1

Step-by-step explanation:

Let the measure of third angle be x

According to the question, each of the remaining two angles are twice of x.

Third angle = x

Each equal angle = 2x

Sum of all angles of a triangle = 180°

x + 2x + 2x = 180°

5x = 180°

x = \dfrac{180 \degree}{5}x=

5

180°

x = 36°

Therefore, third angle = x = 36° and each equal angle = 2x = 2( 36° ) = 72°

Answer 2

answer

Let  third angle be x 

Therefore, two equal angles are 2x and 2x. 

Now, we know that sum of angles of three angles of a triangle is 180∘. 

⇒x+2x+2x=180∘ 

⇒5x=180∘

⇒x=36∘

Hence, the three angles of the triangle are, 

First angle =36∘ 

Second angle =72∘ 

Third angle =72∘ 

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