Question

each of two equal angles of a triangle is twice the third angle find the angles of the triangle

Answer 1

let the 1st and second angle of triangle=X
the 3nd angle of triangle=2x
X +X+2x =180°
4x=180°
X =180°÷4
=45°
3rd angle 2x
= 2×45
=90°
1st angle =45°
2nd angle= 45°
3rd angle= 90°
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Answer 2

Answer:

answer in the picture above

Step-by-step explanation:

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