each of two equal side of a triangle are 4 m less than three time the third side.
Find the dimensions of the triangle, if it's perimeter is 55 m
it's answer is
side of triangle are 23 m, 23 m and 9 m
Answers
Answered by
11
HELLO DEAR,
LET THE THIRD SIDE BE X METER.
EACH TO SIDE BE (3X-4)
GIVEN THAT:-
55=X+2(3X-4)
55=X+6X-8
7X=63
X=9
=>(3×9-4)=23
I HOPE ITS HELP YOU DEAR,
THANKS
LET THE THIRD SIDE BE X METER.
EACH TO SIDE BE (3X-4)
GIVEN THAT:-
55=X+2(3X-4)
55=X+6X-8
7X=63
X=9
=>(3×9-4)=23
I HOPE ITS HELP YOU DEAR,
THANKS
devanshlodhi:
thanks bro
Answered by
2
HEYA!!!!
Given,
perimeter of triangle = 55 cm
Each of 2 equal side of a triangle are 4 less than the three time the third time.
Hence,
let the third side be " x "
Then the two sides = ( 3x-4)
Perimeter of isosceles triangle = sum of all three sides.
ATP,
55 = x + 2 ( 3x-4)
55 = x + 6x - 8
63 = 7x
x = 63/7
x = 9..
Therefore, the sides are 3x - 4 = 3 ( 9 ) - 4 = 23..
HOPE THIS HELPS U @MP#MAHABOOBPASHA#☺☺
Given,
perimeter of triangle = 55 cm
Each of 2 equal side of a triangle are 4 less than the three time the third time.
Hence,
let the third side be " x "
Then the two sides = ( 3x-4)
Perimeter of isosceles triangle = sum of all three sides.
ATP,
55 = x + 2 ( 3x-4)
55 = x + 6x - 8
63 = 7x
x = 63/7
x = 9..
Therefore, the sides are 3x - 4 = 3 ( 9 ) - 4 = 23..
HOPE THIS HELPS U @MP#MAHABOOBPASHA#☺☺
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