Each of two equal sides of a triangle is 3 cm less than the twice the third side. If the perimeter of the triangle is 69 cm find the length of its side
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ab=x
ac=x
bc=x-3
ab+bc+ac=69
x+x-3+x =69
3x-3=69
3x=69+3
3x=72
x=72/3
x=24
ab=ac=24
bc=24-3
=21
ac=x
bc=x-3
ab+bc+ac=69
x+x-3+x =69
3x-3=69
3x=69+3
3x=72
x=72/3
x=24
ab=ac=24
bc=24-3
=21
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