Question

Each person in a group has one pet. Seven people have a dog, 1 person has a bird, and 6 people have a cat. What is the probability of a person having a cat or a bird?

Answer 1

Answer:

1/2

Step-by-step explanation:

Each person in a group has one pet .

Seven people has a dog .

One person has a bird ,

Six people have a cat .

∴ Total number of possibilities = 6 + 1 + 7

= 7 + 7

= 14

P ( having a cat or bird ) = total number of favourable outcomes / total number of possible outcomes .

P ( having bird or cat ) = favourable outcomes / 14

Favourable outcomes = 6 + 1 = 7 .

Hence P ( E ) = 7/14 = 1/2

The probability is 1/2 .

Answer 2

ANSWER:---------

1//2

hope it helps..

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