Question

each piller in a temple is in the shape of a radius 1.4 m and height 4m.find curved surface area of 50 such pillars​

Answer 1

Answer:

$2\pi r(h+r)$ = CSA of a Cylinder

2 (22/7) (1.4) (4+1.4)

=> 44/7 (1.4)(5.4)

=> 49.52m sq

For 50 such pillers

49.52 * 50 = 24760m²