Question

Each question carries 2 marks:
76. The H.C.F. of 6(x2-9) and 15(x3-27) is
a) 90(x-3)
b)3(x+3)
c)3(x2-9)
d) 3(x-3)

Answer 1

Answer:

$c. = 3( {x}^{2} - 9)$

Answer 2

c.=3(x 2−9)✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️