Question

Each question is of two marks

Q1.Find the area of a triangle two sides of which are 8cm and 11cm

and the perimeter is 32cm.​

Answer 1

Answer:

8√30cm2

Step-by-step explanation:

given 2 sides of triangle=8cm and 11cm

perimeter=32cm

so the 3rd side=32-(8+11)=13

area of triangle=√s(s-a)(s-b)(s-c)

s=a+b+c/2

s=32/2=16

√16(16-8)(16-11)(16-13)

√16(8)(5)(3)

√2(2)(2)(2)(2)(2)(2)(5)(3)

2(2)(2)√2(5)(3)

8√30cm2

Answer 2

Perimeter of triangle=32cm

a+b+c. =32cm

8+11+c. =32cm

19+c. =32cm

c. =32-19

c. =13cm

Third side of triangle=13cm

area ot triangle=

s=a+b+c. =8+11+13 =15cm

2. 2

√s(s-a)( s-b)(s-c)

√15(15-8)(15-11)(15-13)

√15×7×4×2

√840. cm²