Question

each rectangle tile is 40 cm long and 30 cm wide ,how many times will required to cover the floor of a room with length = 4.8 cm ,b=2.4 m​

Answer 1

Step-by-step explanation:

We know that,

100cm = 1m

Hence,

length = 40 cm

=40/100

we get

= 0.4 m

breath = 30 cm

= 30/100

we get

= 0.3 m

the area of rectangular tile is calculate

as,

Area = length × breath

Area = 0.4 m × 0.3 m

we get

= 11.52 m

Total number of tiles required = (Area of square / Area of each tile )

= 11.52 m / 0.12 m

we get

= 96

total number of tiles required to cover the floor

= 96 m

Answer 2

Step-by-step explanation:

Length of the rectangular tile =40 cm

Breadth of the rectangular tile =30 cm

Length of the floor tile =4.8 cm

Breadth of the floor tile =2.4 cm

We know that,

100 cm=1 m

Hence,

Length =40 cm

=40/100 m

We get,

=0.4 m

Breadth =30 cm

=30/100 cm

We get,

=0.3 m

The area of rectangular tile is calculated as,

Area = Length × Breadth

Area =0.4 m×0.3 m

We get,

=0.12 m2

The area of the follr is calculated as,

Area = Length × Breadth

Area =4.8 m×2.4 m

We get,

=11.52 m2

Total number of tiles required = (Area of the floor)/ (Area of each tile)

=11.52 m2/0.12 m2

so that we get 96 and

96 tiles is the answer