Each rectangular tile is 40 cm long and 30 cm wide how many tiles are required to Cover the Floor of a room with length 4.8 m and breadth 2.4 m
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Answer:
96 tiles
Step-by-step explanation:
firstly we need to find the area of a tile.
then the area of the room.
divide the area of the room by the area of a tile .
area of rectangle = l * b = length * breadth
area of tile = l * b = 40 * 30 = 1200 sq.cm --( 1 )
area of room= (units are different .therefore we must convert it into cm)
=480 cm * 240cm= 115200 sq.cm----( 2 )
no. of tiles required = area of the room / area of 1 tile
= 115200/1200
=96 tiles
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