Physics, asked by musabh412, 7 months ago

Each resistance in following diagram is of 1 ohm. calculate the total resistance

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Answered by gayatri6323
1

Answer:

pic is not clear plz repeat it.

Answered by davisshikhar
1

Hey mate for this question you need to know the symmetric Circuits

Refer the attachment for Diagram and few details

Form the diagram(Attchment waali) It is clear that each wire has 2 resistances are in series

Hence for each wire Equivalent resistance is given by

R=_{s}=R_{1}+R_{2}=1+1=2ohm

Each wire has a resistance of 2 ohm and are in parallel

hence Resultant (Total) Resistance is given by

\frac{1}{R_{p}}=\frac{1}{R_{1}}\frac{1}{R_{2}}+\frac{1}{R_{3}}

\frac{1}{R_{p}}=\frac{1}{1}+\frac{1}{1}\frac{1}{1}=3

\frac{1}{R_{p}}=3

R_{p}=\frac{1}{3}

The resultant resistance is

\red{R_{equivalent}=\frac{1}{3}\:or\:0.33}

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