Each side of a cube is 3 units. It is cut into cubes each of side 1 unit What is the total surface area of
the smaller cubes thus obtained?
Answers
- We are given that each side of a cube is 3 units and we are cutting it into multiple cubes of side 1 unit each.
- We have to find total surface area of all such 1 unit cubes.
- So initial total volume = 3 * 3 * 3 units
= 27 unit^3.
- And each small cube has total volume
= 1 unit^3.
- So we have total 27 small cubes with total surface area of each cube
= 6 * (side length)^2.
- So each small cube will have total surface area :
= 6 unit^2.
- And so total surface area of all such small cubes:
= 27 * 6 unit^2.
= 162 unit^2.
Given :
The each side of cube = a = 3 units
The cube is cut into other cubes each of side = b = 1 unit
To Find :
Total surface area of the smaller cubes
Solution :
Since , each side of bigger cube = a = 3 unit
So, Total surface area of bigger cube = 6 × a²
i.e Total surface area of bigger cube = 6 × (3 unit)²
∴ Total surface area of bigger cube = 54 sq unit
And, Volume of bigger cube = a³
i.e = ( 3 unit )³
Or, Volume of bigger cube = 27 cubic unit
Now,
The bigger cube is cut into smaller cube of side 1 unit
So, Volume of smaller cube = b³
i.e = ( 1 unit )³
Or, Volume of smaller cube = 1 cubic unit
So, Number of smaller cube =
Or, n =
∴ number of smaller cubes = 27
Again
Total surface area of smaller cubes = 6 × b²
= 6 × 1² = 6 sq unit
Total surface area of all 27 smaller cubes = total number of cubes × 1²
∴ = 27 × 6
= 162 sq unit