Question

Each side of a cube is measured to be 7.203 m. What are the total Surface area and the volume of the cube to appropriate significant figures?

Answer 1

ANSWER:

• T.S.A of cube = 311.3 m²

• Volume of cube = 373.7 m³

GIVEN:

• Side length of cube = 7.203 m

TO FIND:

• Total Surface area and the volume of the cube to appropriate significant figures

FORMULAE:

• T.S.A of cube = 6a²

• Volume of cube = a³

EXPLANATION:

T.S.A of cube = 6a²

a = 7.203 m

6a² = 6(7.203)²

6a² = 6(51.883209)

6a² = 311.299254

IN MULTIPLICATION THE RESULTS SHOULD BE ROUNDED OFF TO THE SAME SIGNIFICANT FIGURES AS THAT OF QUESTION.

T.S.A of cube = 311.3 m² ( Since the significant figures of 7.203 is four)

Volume of cube = a³

a³ = (7.203)³ = 373.714

IN MULTIPLICATION THE RESULTS SHOULD BE ROUNDED OFF TO THE SAME SIGNIFICANT FIGURES AS THAT OF QUESTION.

Volume of cube = 373.7 m³ ( Since the significant figures of 7.203 is four)

Answer 2

$\bf \ Problem : -$

Each side of a cube is measured to be 7.203 m. What are the total Surface area and the volume of the cube to appropriate significant figures?

$\bf \ \: Answer : -$

★Surface area of cube =311.29925m²

★Volume of the cube=373.7m³

$\bf \ \: Solution : -$

The number of significant figures in the measured length L(7.203m) is 4.

Therefore, the calculated surface area of (6 faces of the cube) and volume should be rounded off to 4 significant figures only.

_________________________________

Surface area of cube=6L²

_________________________________

Surface area of cube=6L²

=6(7.203)² m²

=311.29925 m ²

_________________________________

Volume of the cube=L³

__________________________________

Volume of the cube=L³

=(7.203)³m³

=373.71475m³

therefore,

Surface area of cube=311.3m²

Volume of the cube=373.7m³