Each side of a cube is measured to be 7.203 m. What are the total Surface area and the volume of the cube to appropriate significant figures?
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Answer:It is given that the side of the cube is 7.203m. Therefore, number of significant figures in length is 4.Total surface area of cube,S = 6( area of one face) = 6l2 = 6 (7.203)2S = (311.29925) m2By rounding off it to 4 significant figures, we get,S = 311.3 m2Volume of the cube, V = l3 = (7.203)3 = 373.714754427 m3By rounding off it to 4 significant figures, we get,V = 373.7 m3
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➠ANSWER:
- T.S.A of cube = 311.3 m²
- Volume of cube = 373.7 m³
➠GIVEN:
- Side length of cube = 7.203 m
➠TO FIND:
◉Total Surface area and the volume of the cube to appropriate significant figures
➠FORMULAE:
- T.S.A of cube = 6a²
- Volume of cube = a³
➠EXPLANATION:
T.S.A of cube = 6a²
a = 7.203 m
6a² = 6(7.203)²
6a² = 6(51.883209)
6a² = 311.299254
T.S.A of cube = 311.3 m² ( Since the significant figures of 7.203 is four)
Volume of cube = a³
a³ = (7.203)³ = 373.714
Volume of cube = 373.7 m³ ( Since the significant figures of 7.203 is four)
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