Question

Each side of a cube is measured to be 7.203 m. what is (i) the total surface area and (ii) the volume of the cube to appropriate significant figures ​

Answer 1

Answer:

It is given that the side of the cube is 7.203m.

Total surface area of cube,

S = 6(area of one face) = 6l2 = 6 (7.203)2

S = (311.29925) m2

S = 311.3 m2 (after rounding off)

Volume of the cube, V = l3 = (7.203)3 = 373.714754427 m3

V = 373.7 m3 (rounded off)

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Answer 2

$\large\bf {\orange {\underline { \underline {Gíven}} : - }}$

• Length of a side = 7.203 m

$\large\bf {\orange {\underline { \underline {To \: fínd}} : - }}$

(i) the total surface area and

(ii) the volume of the cube to appropriate significant figures

$\large\bf {\orange {\underline { \underline {Solutíon}} : - }}$

we know ,

(i) the total surface area = 6a²

$\longrightarrow \sf 6 \times 7.203 \times 7.203 = 311.29$

This is to be rounded off to 4 significant figures as 7.203 as 4 significant figures.

$\therefore$ Total surface area is 311.3 m²

(ii) Volume of the cube = a³

$\longrightarrow \sf 7.203 \times 7.203 \times 7.203 = 373.71$

This is to be rounded off to 4 significant figures as 7.203 as 4 significant figures

$\therefore$ the volume is 373.7 m³