each side of a cube is measured to be 7.20m.what are the total surface area and the volume of the cube to appropriate significant figures?
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Answer:
It is given that the side of the cube is 7.203m.
Total surface area of cube,
S = 6(area of one face) = 6l2 = 6 (7.203)2
S = (311.29925) m2
S = 311.3 m2 (after rounding off)
Volume of the cube, V = l3 = (7.203)3 = 373.714754427 m3
V = 373.7 m3 (rounded off)
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It is given that the side of the cube is 7.203m. Therefore, number of significant figures in length is 4.
Total surface area of cube,
S = 6( area of one face) = 6l2 = 6 (7.203)2
S = (311.29925) m2
By rounding off it to 4 significant figures, we get,
S = 311.3 m2
Volume of the cube, V = l3 = (7.203)3 = 373.714754427 m3
By rounding off it to 4 significant figures, we get,
V = 373.7 m3
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