Each side of a rectangle is doubled. Find the ratio between perimeters of the of the original rectangle and the resulting rectangle. Also find the area of the original rectangle and the resulting rectangle.
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Let the sides of first rectangle be 'l' and 'b'. That implies second rectangle sides 2l and 2b.
Perimeter of original rectangle is 2(l+b) and resulting rectangle is 2(2l+2b).
Ratio of perimeter = 2(l+b)/ 4(l+b)
= 1/2 =1:2
Area of original rectangle is lb and resulting rectangle is 2l×2b.
Ratio of area = lb/ 4lb =1/4 =1:4
If u found it useful then please mark it as the brainliest.
Perimeter of original rectangle is 2(l+b) and resulting rectangle is 2(2l+2b).
Ratio of perimeter = 2(l+b)/ 4(l+b)
= 1/2 =1:2
Area of original rectangle is lb and resulting rectangle is 2l×2b.
Ratio of area = lb/ 4lb =1/4 =1:4
If u found it useful then please mark it as the brainliest.
tejasreee:
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here is ur ans mate!!!!
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plz mark as brainlist also....
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