Each side of a regular hexagon,inscribed in a circle subtends an angle of 60 degree at the centre and is equal to the radius of circle.prove it
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it may help it is first part
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ksshivam2203:
bhai yaha se second wala prove kar lo
short me bta de na ...ek ques aur h vo b solve krna h
ok
2y+x=180
2y+60=180
i think it may help
after this y=60 so by equilaeral triangle property all angle if equal then all side is equal hence proved
thanksss!!!
ek ques h aur ...APB and CQD are two congurent arcs.prove that AC||BD....ek baar try krna ...if nhi bnega to b bta dena ek baar.
first make both arc then from centre draw a line to a and to b in arc apb then join ab.now in arc cqd from centre draw aline to c and to d now join cd . i think you may do now
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