Question

each side of a rhombus is 10cm long and one of its diagonal measures 16cm find the length of other diagonal and hence find the area of the rhombus



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Answer 1

Heya user ,
Here is your answer !!

The sides of the rhombus is = 10 cm .

Now , one of the diagonal is 16 cm .

So , when the two diagonals intersect , four right angled triangles are formed .

Lets take one right angled triangle .

Applying Pythagoras' theorem , we get ,

AB^2 + BC^2 = AC^2
=> AB^2 + 8^2 = 10^2
=> AB^2 = 10^2 - 8^2
=> AB^2 = 6^2
=> AB = 6 .

Hence , the length of the other diagonal is ( 2 * 6 ) cm = 12 cm .

Hence , the area of the rhombus is
= 1/2 * 12 * 16 sq. cm
= 96 cm ........... [Answer]

Hope it helps you !!

Answer 2

here is ur answer
length of the diagonal is 12cm
and area of rhombus is 1÷2×12×16=96
sry in paper I made a small mistake hope so u will identify