Question

Each side of a rhombus is 13 cm and one diagnol is 10 cm. Find the length of its other diagonal​

Answer 1

Answer:

From the question,

Rhombus ABCD with centre O,

side (S) = 13 cm

shorter diagnol (P) = 10 cm

consider triangle OCB,

applying Pythagoras theorem,

OC = √ (BC^2 - OB^2 ) = √(169 - 25) = √ 144 = 12

OC = 12 cm

longer diagnol (AC) = AO + OC = 2OC = 2 x 12 = 24

Longer diagnol, AC = 24 cm.

Area of rhombus ABCD = [(AC x BD) / 2 ] = 10 x 24 / 2

Area of Rhombus ABCD = 120 sq.cm

Step-by-step explanation:

Answer 2

Answer:

one side rhombus = 13 cm

length of one diagonal = 10 cm

property to use: diagonals of rhombus bisect each other at 90 degree

taking 1/4 portion of rhombus (triangle)

base = 5 cm (half of diagonal)

hypotnuse = 13 cm

for perpendicular use pythagoras theorem

on putting the values in the equation and then solving it we get perpendicular(p)= 12cm

therefore diagonal = 2p= 24cm

Step-by-step explanation: