Each side of a rhombus is 13 cm and the length of one diagonal is 24 cm B Find the area of the rhombus
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the length of the other diagonal is ten
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one side rhombus = 13 cm
length of one diagonal = 24 cm
property to use: diagonals of rhombus bisect each other at 90°
taking 1/4 portion of rhombus (triangle)base = 12 cm (half of diagonal)hypotenuse = 13 cm
for perpendicular use pythagoras theorem
h²-b²=p²
then solving it we get perpendicular(p)= 5 cm
therefore diagonal = 2p= 10 cm
Area of rhombus = 1/2 × 10 × 24
= 120 cm²
:) Hope This Helps!!!
length of one diagonal = 24 cm
property to use: diagonals of rhombus bisect each other at 90°
taking 1/4 portion of rhombus (triangle)base = 12 cm (half of diagonal)hypotenuse = 13 cm
for perpendicular use pythagoras theorem
h²-b²=p²
then solving it we get perpendicular(p)= 5 cm
therefore diagonal = 2p= 10 cm
Area of rhombus = 1/2 × 10 × 24
= 120 cm²
:) Hope This Helps!!!
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