Each side of a rhombus is 15 cm. if the length of one of its diagonals is 18 cm, then what is the length of
the other diagonal?
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Rhombus ABCD, AB= BC= CD= DA = 15 cm diagonal AC = 18 cm & AC & BD intersect at O.
TO FIND: diagonal BD
Since diagonals of a rhombus bisect each other at right angles.
In right triangle AOB
Hypotenuse AB = 15cm , AO = 9 cm
=> BO = √(AB² - AO² )
=> BO = √(15² - 9² )
=> BO = √(24 * 6)
=> BO = √(2² *6² )
=> BO = 12 cm
=> BD= 2BO
=> BD = 2*12
=> BD = 24 cm
Hope it helps
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TO FIND: diagonal BD
Since diagonals of a rhombus bisect each other at right angles.
In right triangle AOB
Hypotenuse AB = 15cm , AO = 9 cm
=> BO = √(AB² - AO² )
=> BO = √(15² - 9² )
=> BO = √(24 * 6)
=> BO = √(2² *6² )
=> BO = 12 cm
=> BD= 2BO
=> BD = 2*12
=> BD = 24 cm
Hope it helps
Thanks
Mark me as brainliest
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