Question

Each side of a rhombus is 26 cm and one of its diagonals is 48 cm long. The area of the rhombus is:

Answer 1

Answer:

The other diagonal=(v26^2-24^2)2

= 20 cm

Area = d 1xd2/2=48x20/2=480 cm2

Answer 2

Answer:

$area \: of \: the \: rhombus \: = 480 {cm}^{2}$

Step-by-step explanation:

Given:

Side = 26 cm

Diagonal = 48 cm

To find:

Area of the Rhombus

Formula :

$\frac{1}{2} \times d \times \sqrt{4 \times {s}^{2} - {d}^{2} }$

Solution :

$\frac{1}{2} \times 48 \times \sqrt{4 \times {26}^{2} - {48}^{2} }$

$\frac{1}{2} \times 48 \times \sqrt{4 \times 676 - 2304}$

$\frac{1}{2} \times 48 \times \sqrt{2704 - 2304}$

$\frac{1}{2} \times 48 \times \sqrt{400}$

$\frac{1}{2} \times 48 \times 20$

$48 \times 10$

$480 \: {cm}^{2}$