Question

Each side of a small cubical box is 6 cm. There is another big cubical box whose each
side is double of the small box. How many small boxes will fit in the big box?​

Answer 1

Answer:

refer to the image for answer

Answer 2

Given:

Side, s = 6 cm

Solution:

First small cubical box:

Volume of cube = s^3

V = 6^3 = 216 cm^3


Second big cubical box:

Side, s = 2(6) = 12 cm

V = s^3 = 12^3 = 1,728 cm ^3

Then, divide the big cubical box to the small cubical box to find how many boxes will fit in it.

V = 1,728 cm ^3 / V = 216 cm^3

= 1728 / 216

= 8

Therefore, there are 8 small boxes needed to fit in the big box.


Hope this will be helpful to you.