Question

Each side of a small cubical box is 6 cm. There is another big cubical box whose each
side is double of the small box. How many small boxes will fit in the big box? ​

Answer 1

Answer:

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Step-by-step explanation:

Answer 2

Solution:

Given:

Side, s = 6 cm

Volume of cube = s^3

V = s^3 = 6^3 = 216 cm ^3

The volume for the small box is 216 cm^3

Then for the bigger box, double the side = 2(6) = 12 cm

V = s^3 = 12^3 = 1728 cm^3

Then divide the two volumes.

V = 1728 cm^3 / 216 cm ^3 = 8

Therefore, there are 8 small boxes needed to fit in the big box.

Hope this will be helpful to you.