Question

Each side of a square field measure 21m adjacent to this field there is rectangular field having its sides in the ratio 4:3 If the perimeters of both the field are equal. Find the limensins of the rectangular field.

Answer 1

Solution:-

side of the square field= 21m

perimeter of the square field= 4×21m

= 84m

let the length and breadth of the rectangular field be 4x and 3x - respectively

peri of the rectangular field = 2 (l+b) m

= 14xm

Perimeter of the rectangular field= Perimeter of the square field therefore.

14x=84. = 84/14 = 6

L oc rec field = (4x6)m = 24m

B of rec field = (3x6)m = 18 m

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Answer 2

Answer:

SinCe it is given that perimeter of rectangle=perimeter of square

I.E.=2(l+b) = 4×S

since sides of rectangle are in ratio of 4:3

take length as 4x and breadth as 3 x

so according to condition

2(4x+3x)=4×21(sides of square is given 21m)

4x+3x=84/2=42

7x=42

x=42/7=6

x=6

so length of rectangle is 4x=4×6=24m

and breadth is 3x=3×6=18m

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