Each side of a square field measure 21m.Adjacent to this field there is a rectangular field having its sides in the ratio 4:3.If the perimeters of both the field are equal.Find the dimension of the rectangular of the rectangular field.
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Perimeter of the square field= 4×side
= 4×21
=84m²
Let the field's side be 4x and 3x.
Perimeter of the rectangular field= 2(4x+3x)
84=8x+6x
84=14x²
x=84/14
x=6
So actual length=4x=4×6=24
breadth= 3x=3×6= 18
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