each side of a square field measures 21 m. adjacent to this field there is a rectangular field having its sides in tje ratio 4:3 . If the perimeters of both the fields are equal. find the dimensions of rectangular field.
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4x+3x=21
7x=21
x=21÷7
x=3
4x=4×3=12
3x=3×3=9
7x=21
x=21÷7
x=3
4x=4×3=12
3x=3×3=9
VishalSwabhimani:
Plz help me
Dimmenson are 9 and 12
2 (4+3)X=21
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