Each side of a square is of length 4 units. The centre of the square is (3, 7) and one of its diagonal is parallel to y = x. Find the co-ordinates of its vertices.
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Step-by-step explanation:
R.E.F image
Let ABCD in square
AB=CD=DA=BC=?
P=(3,7)
draw PM
⊥
AB
M is mid point of AB
So, AM=MB=PM=?
diagonal is parallel to y = x, its sides
are parallel a to coordinate axis
∴ M = (3, 5)
⇒ A= (3 - 2, 5) = (1, 5)
B = (3 + 2 + 5) = (5, 5)
C = (3 + 5, 7 + 2) = (8, 9)
D = (3 - 2, 7 + 2) = (1, 9)
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