Question

each side of a squre room measure 6m. triangular tiles measuring 6cm,8cm and 10cm are to be fitted on the floor. find the number of tiles required.
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Answer 1

Answer:

Area of sq. room=(600)²=360000 sq. cm

Area of ∆:

s=(6+8+10)/2=12

Area=√[s(s-a)(s-b)(s-c)]

=√[(6×2)(6)(2×2)(2)]

=6×4

Area of each tile=24 sq. cm

Number of tiles required=Area(Sq.)/Ar.∆

=360000/24=15000

∴ The number of tiles rquired are 15,000

Answer 2

Answer:

Step-by-step explanation:

length of side of room=6m

                                    =600cm

legths of triangle:-

            a=6cm

            b=8cm

            c=10cm

area of room= (600)²

                     =360000cm²

semi-perimeter(s) of triangle=$\frac{6+8+10}{2}$

                                               =$\frac{24}{2}$

                                               =12cm

area of tiles=$\sqrt{s(s-a)(s-b)(s-c)}$

                   =$\sqrt{12(12-6)(12-8)(12-10)}$

                   =$\sqrt{12*6*4*2}$

                   =$\sqrt{4*3*3*2*4*2}$

                   =4*3*2

                   =24cm²

no. of tiles it takes to cover the floor=$\frac{360000}{24}$

                                                            =15000 tiles

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