Question

Each side of an equilateral triangle is 10 cm. Find (i) the area of the triangle and (ii) the height of the triangle.​

Answer 1

Answer:

i)Area of traingle =1/2*10*10=50

Step-by-step explanation:

2)

Answer 2

Given ,

• The side of equilateral triangle is 10 cm

We know that , the area of equilateral triangle is given by

$\large{ {\boxed{ \sf{Area = \frac{ \sqrt{3} }{4} \times {(side)}^{2} }}}}$

Thus ,

$\sf \mapsto Area = \frac{ \sqrt{3} }{4} \times {(10)}^{2} \\ \\\sf \mapsto Area = \frac{ \sqrt{3} }{2} \times 50 \\ \\\sf \mapsto Area = 25 \sqrt{3} {cm}^{2}$

$\sf \therefore \underline{The \: area \: of \: equilateral \: triangle \: is \: 25 \sqrt{3} \: {cm}^{2}}$

Now ,

$\boxed{ \sf{Area = \frac{1}{2} \times base \times height}}$

Thus ,

$\sf \mapsto 25 \sqrt{3} = \frac{1}{2} \times 10 \times height \\ \\ \sf \mapsto 25 \sqrt{ 3} = 5 \times height \\ \\ \sf \mapsto height = 5 \sqrt{3} \: \: cm$

$\sf \therefore{ \underline{The \: height \: of \: equilateral \: triangle \: is \: 5\sqrt{3} \: cm }}$