Question

each side of an equilateral triangle measures 8cm. find the area​

Answer 1

Answer:

16√3

Step-by-step explanation:

AREA OF AN EQUILATERAL TRIANGLE = √3 x SIDE² / 4

= √3 x 8 x 8 / 4

= 16√3

Answer 2

Answer:

$8\sqrt{5}$$cm^{2}$

Step-by-step explanation:

By Pythagoras Theorem,

base=4cm

hypot.=8cm

height=$\sqrt{8^{2}+14^{2} }$

         =$\sqrt{80}$

         $=4\sqrt{5}$cm

F(x) for area is b/2 into height

=$\frac{4}{2}$*$4\sqrt{5}$

=$2*4\sqrt{5}$

=$8\sqrt{5}$$cm{2}$