Question

Each side of an isosceles triangle is 15 cm and perimeter of the triangle is 50m.find the third side​

Answer 1

$\huge{\underline{\overline{\mid{\mathfrak{\purple{\:\: SOLUTION\:\:} \mid}}}}}$

$\underline{ \mathfrak{ \: AnswEr:- \: }}$

$\sf{\blue{The \: \: third\: \: side \: \: of\: \: isosceles \: \: \triangle = \underline{ \: 20cm \: }}}$

$\underline{ \mathfrak{ \: Given:- \: }}$

$\text{ \orange{Each side of an isosceles triangle = 15 cm }} \\ \text{ \orange{The perimeter of the isosceles triangle = 50m}}$

$\underline{ \mathfrak{ \: Need \:\: to \:\: find:-\: }}$

$\sf{\green{The \: \: third\: \: side \: \: of\: \: isosceles \: \: \triangle =\: ?}}$

$\underline{ \mathfrak{ \: Let:- \: }}$

$\sf{\pink{The \:third \:side \:of\: the \:\triangle = \:y}}$

$\underline{ \mathfrak{ \: \:As,\:we \: \: know \: \: that:- \: \: }}$

$\: \: \: \: \: \: \: \: \: \: \: \sf{Perimeter\:of\:the\:\triangle = Sum \: of \: all \: sides}$

$\underline{ \mathfrak{ \: Putting\:\:the\:\:values:- \: }}$

$\sf{ \longrightarrow \: 50cm = 15cm + 15cm + y}$

$\sf{ \longrightarrow \: 50cm = 30cm + y}$

$\sf{ \longrightarrow \: y = 50cm - 30cm }$

$\longrightarrow{\gray{\boxed{\underline{\underline{\blue{ \tt y = 20cm }}}}}}$

$\underline{ \mathfrak{ \: \: Therefore:- \: \: }}$

$\sf{\green{The \: \: third\: \: side \: \: of\: \: isosceles \: \: \triangle = \underline{ \: 20cm \: }}}$

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Answer 2

$\sf\red{Given:}$

Each side of isosceles triangle=15 cm

Perimeter of triangle=50m

$\sf\green{To\:find:}$

The third side of the triangle.

$\sf\pink{Solution:}$

We know that in a Isosceles triangle the two sides are equal.

Now,

$\sf\underline\blue{Perimeter\:of\:Δ=Sum\:of\:three\:sides}$

Let the third side of the triangle be x

A/Q

50=15+15+x

50=30+x

50-30=x

x=20

$\sf\fbox{x=20 cm}$

Therefore the third side of the Triangle is 20 cm respectively.

Hope it's helpful!