Question

each side
of cube is decreased by 50%, let us
calculate the volume ratio of original and changed

cube.​

Answer 1

Answer:

$\sf \: \: let \: the \: edge \: of \: cube \: be \: x \: units \\ \\ \sf \: decreased \: edge = \frac{x}{2} \\ \\ \sf \: volume \: of \: changed \: cube = {a}^{3 } \\ \\ \implies \: \sf \frac{x}{2 } \times \sf \frac{x}{2} \times \frac{x}{2} = \frac{ {x}^{3} }{8} \\ \\ \sf \: volume \: of \: original \: cube = {x}^{3} \\ \\ \sf Req. \: \: ratio = {x}^{3} : \frac{ {x}^{3} }{8} \\ \\ \implies \sf \: 8: 1$