each side of rhambus is 3√5 and it's one diagonal is twice the other then find the other area of quadrilateral?
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Each side of the rhombus = 3√5 cm
If one diagonal is twice the other let them be say 2x and 4x.
x^2+(2x)^2=[3√5]^2
x^2+4x^2 = 45, or
5x^2=45, or
x = {45/5]^0.5 = 3
So the diagonals of the rhombus are 6 cm and 12 cm. And the area of the rhombus = 6x12/2 = 36 sq cm. Answer
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