Each side of rhombus is 61 cm and one of its diagonals is 22 cm find 1. the length of the other diagonal 2. the area of the rhombus.
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Diagonals of a rhombus bisect each other at right angles.
Let ABCD be the rhombus, Diagonal AC= 16 cm and side AB = 10 cm.
In right triangle AOB, AB = 10 cm, AO = 8 cm
By Pythagoras theorem, AB2 = AO2 + BO2
(10)2 = (8)2 + BO2
BO2 = (10)2 – (8)2
BO = 6 cm
Diagonal BD = 2 x 6 = 12 cm
Hence length of other diagonal = 12 cm; Area of rhombus = 96 cm2
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