Question

Each sides of a rhombus is 13 cm and one diagnol is 10 cm find the length of another diagnol and the area of the rhombus

Answer 1

Answer:

Step-by-step explanation:

Let ABCD be the rhombus

AB=BC=CD=AD=13 cm

BD=10 cm  and AC=?  (BD and AC are the diagonals)

Diagonals of a rhombus bisect each other perpendicularly

By Pythagoras Theorem,

AD²=AE²+ED²(E is the point intersection of the 2 diagonals)

13²=AE²+25²

AE²=144

AE=12 cm

AC=2×12 cm

Area of rhombus=1/2×d1×d2

                              =1/2×12×10

                                  =60cm²