each term in the following sequence is 6 more than the previous term what is the value of x + Z? X, y, Z, 7, 13...
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Answer:
-10
Step-by-step explanation:
t1=X
t2=y
t3=Z
t4=7
t5=13
common difference d= 6
therefore,
t4=t3+d
7= t3+6
t3= 7-6
t3=1=Z
Z=1
t3=t2+d
1 = t2+6
t2= 1-6
t2= -5 = y
y= -5
t2= t1+ d
-5= t1+6
t1= -5 -6
t1= -11 =X
X = -11
therefore,X + Z= (-11) + 1
X+Z = -10
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