Each term of an AP whose first term is a and common difference d is doubled .Is the resulting sequence an AP? If no find its first term and cd
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The general form of an AP is a, a+d, a+2d,.....
where a is the first term and d is the common difference
If we double the terms, the new sequence would be
A , a+2d, a+4d,......
We can observe that this sequence is also an AP
First term is a
Common difference is 2d nth term= 2a+(n-1)2d = 2[a+(n-1)d]
albin50:
Thanks
Answered by
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when first term = a
and common difference = d
then AP series is a, a+d, a+2d,.....
when it doubles 2a, 2(a+d),2(a+2d).....
then first term =2a
and common difference = 2d
and common difference = d
then AP series is a, a+d, a+2d,.....
when it doubles 2a, 2(a+d),2(a+2d).....
then first term =2a
and common difference = 2d
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