Question

Each triangular face of the Pyramid of Peace in Kazakhstan is made up of 25 smaller

equilateral triangles. These triangles have measurements as shown in the diagram. What is the

area of one of the smaller equilateral triangle​

Answer 1

Explanation:

base = 12m height = 10.4m

area of triangle =1/2 bh

=1/2 (12)(10.4)

= 62.4sqm.

Answer 2

Given:

The triangular face of the Pyramid is 25 smaller equilateral triangles.

To find:

area of equilateral triangle =?

Explanation:

• Let b be the breadth of the triangle & h be the height of the triangle.

• To find the length of the base and the height of the triangle.

• Consider b = 12 m and h = 10.4 m

• By using the formula to find the area of the triangle.

          $\displaystyle A = \frac{1}{2}\ b\ h$

              = 0.5 (12)(10.4)

          A = 62.4 $\mathbf{m^2}$

The required area of one small equilateral triangle is 62.4 $m^2$.