Question

Each unit of food X costs Rs. 25 and contains 2 units of protein and 4 units of iron while each unit of food Y costs Rs.

30 and contains 3 units of protein and 2 units of iron. Each animal must receive at least 12 units of protein and 16 units of

iron each day. How many units of each food should be fed to each animal at the smallest possible cost?


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Answer 1

Answer:

Step-by-step explanation:

LET p BE PROTEIN AND i BE IRON

X=2p+4i   . . . . (1)       X contains 6 unit therefore 6*25=150 RS

Y=3p+2i    . . . .  .(2)      Y contains 5 unit therefor 5*30=150 RS

Multiplying (1) by 3 and (2) by 2

3X=6p+12i                   X should contain 18 unit therefore 18*25=450 RS

2Y=6p+4i                  Y should contain 10 unit therefore 10*30=300 RS

adding both

3X+2Y=12p+16i    .. . .  so required condition satisfied.

Final Answer

18 unit of food X is required Which costs 450 RS

10 unit of Food Y is required which costa 300 RS

TOTAL Amount =450+300=750 RS