Each year a tree grows 5 cm less than it did the preceding year. If it grew by 1 m in the last year, it eased growing. Find that, in which year does it stop its growing ?
nellimtaknev:
Anyone please help me.............
Because its too urgent..........
Please check the sum properly. The sum may not be correct.
whatttt?????????? i did not completely understand the question.
Answers
Answered by
202
hey its part of an Arithmetic progression
an Arithmetic progression(AP) is a sequence of numbers in which each differs from the preceding one by a constant quantity
in which
a(first term) = 100 cm
d(common difference) = - 5cm
An(nth term) = 0cm
n = ?
therefore
An = a + (n-1)d
0 = 100 - 5n + 5
-105 = - 5n
21 = n
hence in the 21 st year the tree will stop growing
pleazzzzzzzzzzzzzz mark the best
an Arithmetic progression(AP) is a sequence of numbers in which each differs from the preceding one by a constant quantity
in which
a(first term) = 100 cm
d(common difference) = - 5cm
An(nth term) = 0cm
n = ?
therefore
An = a + (n-1)d
0 = 100 - 5n + 5
-105 = - 5n
21 = n
hence in the 21 st year the tree will stop growing
pleazzzzzzzzzzzzzz mark the best
thanks
Answered by
3
Answer:
a=100 com
d=-5com
Sn=a+(n-1)d
0=100-5n+5
Step-by-step explanation:
so, when u will solve it u will get answer as n=21
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