Question

EAN of Nickel in [Ni(en)2]+2 is..
​

Answer 1

Answer:

EAN of Nickel in [Ni(en)2]+2 is 34 , i.e the complex is unstable.

Explanation:

EAN = (Total no of electron contributed from metal ion - charge of metal ion)+ (no of electron contributed from ligands)  

EAN= (28-2)+(2*4) =34                                                                                        

Answer 2

EAN of Ni is 34.

Given: $[Ni(en)_2]^{+2}$

To find: We have to find the EAN.

Solution:

The given complex is $[Ni(en)_2]^{+2}$.

Let oxidation state of Ni is x.

Thus we can write-

$x + 0 = + 2 \\ x = + 2$

The atomic number of Ni is 28.

Thus EAN= atomic number of Ni-oxidation state of Ni+2×number of Ligands.

Here en is a bidentate ligands.

EAN=28-2+2×4

EAN=34

EAN of Ni is 34.