Eand F are respectively the mid point of the side AB and AC of∆ABC show that BF=CE
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Given:a triangle ABC in which E and F are midpoint.
To Prove:BF=CE
Proof:In triangle ABE and ACF
AB=AC(E and F are midpoint)
angle A =angle A (common)
angle B=angle C(given)
By the axiom AAS
triangle ABE congruent triangle ACF
so,
CF=CE (c.p.c.t)
hope it helped you..
...
To Prove:BF=CE
Proof:In triangle ABE and ACF
AB=AC(E and F are midpoint)
angle A =angle A (common)
angle B=angle C(given)
By the axiom AAS
triangle ABE congruent triangle ACF
so,
CF=CE (c.p.c.t)
hope it helped you..
...
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