Question

Eand F are respectively the midpoints of equal sides ab and ac of a triangle ABC show that bf equal CE ​

Answer 1

Answer:

AB=AC

angle ABC=angle ACB

In triangle EBC AND FCB,

BE=FC[1/2 of equal sides]

angle ABC= ACB

BC as common.

triangle EBC IS CONGRUENT TO TRIANGLE FCB BY S.A.S. CONGRUENCY.

SO,EC=FB(C.p.c.t)

Answer 2

Answer:

BF=CE

Step-by-step explanation:

E is mid point

AE=EB=AF=FC

IN ∆EBC AND FCB

EB=FC

BC=BC

angleE=ANGLE F

∆EBC~=∆FCB

EC=FB