Question

earning Task 1. Write the letter before the number. The letters will spell out
he Khmer greeting.
1. What is the 5th term of the arithmetic sequence an= 5n + 1 ?
G. 23
H. 24
I. 25
J. 26
2. What is the next 3 terms of the Fibonacci sequence 0, 1, 1, 2, 3, 5,...?
T. 8, 10, 18
U. 8, 13, 21
V. 8, 12, 16
W. 8, 11, 14
3. What are the missing numbers in the sequence 4, ---, -, -, 64 ?
M. 8, 16, 32
N. 8, 14, 28
0.8, 18, 28
P. 8, 12, 16
4. What is the common ratio of the given sequence 3, -6, 12,-24, 48 ?
R. 2
S. 3
T. -3
5. What is the 10th term of the arithmetic sequence an = 3n - 5 ?
I. 25
J. 30
K. 35
L. 40
6. If ai = 2, d = -2, then what is a12?
T. -20
U. -22
V. 20
W.22
7. What is the common ratio of the given sequence 1000, 500, 250, 125?
R.
Q. -2
S.
P. 2
the form of the sequence -10,
8, -6, -4,
...?
Q. -2
1
1​

Answer 1

Answer:

in question 7

common ratio = a2/a1

= 500/1000

= 1/2

Answer 2

Given : arithmetic sequence aₙ= 5n + 1

To Find : 5th term

G. 23

H. 24

I. 25

J. 26

Solution:

aₙ= 5n + 1

for 5th term n = 5

=> a₅ = 5(5) + 2

=> a₅ = 26

Hence correct option is J) 26

next 3 terms of the Fibonacci sequence 0, 1, 1, 2, 3, 5,...?

Fibonacci sequence Tₙ = Tₙ₋₁ + Tₙ₋₂  where T₁ = 0 , T₂ = 1

3 + 5 = 8

5 + 8 = 13

8 + 13 = 21

8 , 13 and 21

Correct option is U. 8, 13, 21

missing numbers in the sequence 4, ---, -, -, 64

Geometric sequence

A sequence of numbers in which the ratio between consecutive terms is constant and called the common ratio.

a , ar , ar² , ... , arⁿ⁻¹

The nth term of a geometric sequence with the first term a and the common ratio r is given by:   aₙ = arⁿ⁻¹

Correct option is M. 8, 16, 32

common ratio of the given sequence 3, -6, 12,-24, 48

-6/3 = - 2

Correct option is  -2

10th term of the arithmetic sequence aₙ = 3n - 5

= 3(10) - 5

= 25

Correct option is I. 25

If a₁ = 2, d = -2, then what is a₁₂

aₙ = a₁ + (n - 1)d

a₁₂ = 2 + (12 -1 )(-2)  = -20

Correct option is T. -20

common ratio of the given sequence 1000, 500, 250, 125

500/1000  = 1/2

the form of the sequence -10, -8, -6, -4, ...

aₙ = 2n - 12

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