Question

easy method to byheart angles in trigonometry ​

Answer 1

Answer:

Just remember the values of sin∅.

Reverse the order of the values to get cos∅.

For tan ∅ use the formula, tan∅=sin∅/cos∅.

For cosec∅, sec∅ and cot∅, take the reciprocal of sin∅, cos∅ and tan∅ respectively.

(in exam you can write down the table on rough page during the reading time.)

Answer 2

#Side ratios

1st method:

$\frac{Pandit}{Har}$ $\frac{Badri}{Har}$ $\frac{Prasad}{Bole}$

See the first letter, Which is similar to:

$\frac{P}{H}$ $\frac{B}{H}$ $\frac{P}{B}$

2nd method:

Some People Have Curly Black Hair Turns Permanently Black

Remember this line..Here

Some = 'Sin'

People = 'perpendicular'

Have = 'Hypotenuse'

an so on..

#angles

basically in class 10, the angle range, from 0 - 90° is given

just remember the angles value of sin∅

cos∅ is just the opposite of sin∅, that means the values are sideways inverted

eg: if sin0° = 0 then cos0° = 1

if sin30° = 1/2 then cos30° = √3/2

if sin45° = 1/√2 then cos0° = 1/√2

for tan∅ divide sin∅ and cos∅ (Note : the value of ∅ should be same)

cosec∅ is the inverse of sin∅

cos∅ is the inverse of cos∅

cot∅ is the inverse of tan∅ or

CotA = $\frac{cosA}{sinA}$