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Let AC = AB = r = radius of the circle
BC = 20 cm
In ∆ABC,
By using pythagorus theorem,
H² = B² + P²
(BC)² = (AC)² + (AB)²
(20)² = r² + r²
400 = 2r²
r² = 200
r = √200
r = 10√2
Area of circle = πr²
= 22/7 × (10√2)²
= 22/7 × (200)
= 4400/7
= 628/571 cm²
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