Question

Easy question..!

The base radius and height of a right circular cylinder are 5 cm and 10 cm. It's total surface area is

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Answer 1

Answer:

$\bf \: radius \: = 5cm \\ \bf \: height \: = \: 10cm \: \\ \bf \: total \: surface \: area \: = 2 \pi r(r + h) \\ \bf \: 2 \times \frac{22}{7} \times 5(5 + 10) \\ \bf \: 2 \times \frac{22}{7} \times 5 \times 15 \\ \bf \: \frac{3300}{7} \\ \bf \: = 471.4 {cm}^{2}$

Answer 2

Given -

• Base radius of cylinder = 5 cm

• Height of cylinder = 10 cm

To find -

• The total surface area of Cylinder.

Formula used -

• Toral surface area of Cylinder = 2πr(r + h)

Solution -

In the question, we are given with the height and base radius of a right circular cylinder and we need to find it's total surface area. For that we will apply the formula of total surface area of cylinder, for that we should have height, base radius, which we are provided with. Let's do it!

According to question -

Base radius = 5 cm

Height = 10 cm

π = $\sf\dfrac{22}{7}$

Now -

We will apply the formula of TSA of cylinder, by applying the formula of TSA of Cylinder.

Total surface area = 2πr(r + h)

where -

π = $\sf\dfrac{22}{7}$

r = Base radius

h = Height

On substituting the values -

$\sf \: TSA \: = 2 \: \pi \: r(r \: + \: h) \\ \\ \\ \sf \longrightarrow \: TSA \: = 2 \: \times \: \dfrac{22}{7} \: \times 5 \: cm \: (5 \: cm \: + \: 10 \: cm) \\ \\ \\ \sf \longrightarrow \: TSA \: = \: \dfrac{44}{7} \: \times 5 \: cm \: (5 \: cm \: + \: 10 \: cm) \\ \\ \\ \sf \longrightarrow \: TSA \: = 31.42 \: cm \: \times \: 15 \: cm \\ \\ \\ \sf \longrightarrow \: TSA \: = 471.3 \: {cm}^{2}$

$\therefore$ The total surface area of Cylinder is 471.3cm²

More formulae of Cylinder -

$\sf \longrightarrow \: Volume = \pi \: {r}^{2}h$

$\sf \longrightarrow \: curved\: surface\: area \: = 2\pi\: r \: h$

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